mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2022

24 December

The expression \((3x-1)^2\) can be expanded to give \(9x^2-6x+1\). The sum of the coefficients in this expansion is \(9-6+1=4\).
What is the sum of the coefficients in the expansion of \((3x-1)^7\)?

Show answer

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2024

Advent calendar 2023

Advent calendar 2022

Advent calendar 2021


List of all puzzles

Tags

hexagons sequences christmas pentagons chess partitions chocolate averages cryptic crossnumbers products star numbers palindromes chalkdust crossnumber multiplication cubics scales combinatorics complex numbers logic addition consecutive numbers advent proportion indices matrices mean surds tournaments probability sums tangents money gerrymandering differentiation lines axes decahedra shape folding tube maps sport sets digital clocks digital products albgebra speed coordinates spheres doubling 3d shapes polynomials functions irreducible numbers dominos 2d shapes determinants geometric means geometry percentages probabilty digits circles pascal's triangle area range floors remainders cube numbers ave square roots cards the only crossnumber time parabolas crosswords calculus perimeter grids dates even numbers arrows quadrilaterals medians odd numbers triangles division tiling games sum to infinity routes square grids taxicab geometry elections neighbours factors graphs number rectangles means ellipses rugby clocks fractions multiples geometric mean balancing algebra binary crossnumbers unit fractions coins expansions volume triangle numbers regular shapes books integers quadratics squares prime numbers angles median shapes numbers grids factorials square numbers consecutive integers polygons menace people maths dice dodecagons bases planes wordplay cryptic clues perfect numbers symmetry trigonometry integration colouring powers numbers

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2025