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Advent calendar 2022
24 December
All 2022 advent puzzles
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The expression \((3x-1)^2\) can be expanded to give \(9x^2-6x+1\). The sum of the coefficients in this expansion is \(9-6+1=4\).
What is the sum of the coefficients in the expansion of \((3x-1)^7\)?
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The sum of the coefficients can be worked out by substituting \(x=1\) into the polynomial, so the sum of the coefficients is \((3-1)^7\), or
128
.
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consecutive numbers
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range
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even numbers
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chalkdust crossnumber
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