Advent calendar 2019

16 December

Arrange the digits 1-9 in a 3×3 square so that: the median number in the first row is 6; the median number in the second row is 3; the mean of the numbers in the third row is 4; the mean of the numbers in the second column is 7; the range of the numbers in the third column is 2, The 3-digit number in the first column is today's number.
median 6
median 3
mean 4
today's numbermean 7range 2

Show answer


Show me a random puzzle
 Most recent collections 

Advent calendar 2019

Sunday Afternoon Maths LXVII

Coloured weights
Not Roman numerals

Advent calendar 2018

Sunday Afternoon Maths LXVI

Cryptic crossnumber #2

List of all puzzles


integers chess differentiation 3d shapes menace planes coordinates star numbers advent indices triangles bases chocolate factorials complex numbers tiling scales perimeter proportion dominos parabolas median trigonometry shapes mean averages addition crosswords triangle numbers squares polygons sport geometry number means rugby taxicab geometry division regular shapes algebra money chalkdust crossnumber symmetry graphs time odd numbers range surds logic hexagons balancing angles folding tube maps multiples products rectangles 2d shapes functions gerrymandering irreducible numbers probabilty digits calculus integration dates unit fractions numbers shape quadratics factors colouring ellipses coins lines wordplay fractions people maths digital clocks cryptic crossnumbers arrows dodecagons probability clocks multiplication dice perfect numbers spheres speed crossnumbers partitions books the only crossnumber volume sum to infinity elections routes ave grids cryptic clues square numbers cube numbers doubling sequences floors sums prime numbers circles square roots games christmas cards crossnumber remainders pascal's triangle percentages area palindromes


Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2020