mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2018

18 December

There are 6 terms in the expansion of \((x+y+z)^2\):
$$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz$$
Today's number is number of terms in the expansion of \((x+y+z)^{16}\).

Show answer

Tags: algebra

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2019

Sunday Afternoon Maths LXVII

Coloured weights
Not Roman numerals

Advent calendar 2018

Sunday Afternoon Maths LXVI

Cryptic crossnumber #2

List of all puzzles

Tags

books planes parabolas sequences trigonometry rugby square numbers menace chess complex numbers addition probabilty partitions coins prime numbers symmetry doubling spheres remainders averages multiplication money volume factorials means bases perfect numbers integration shapes arrows christmas angles clocks floors algebra scales triangle numbers probability 3d shapes square roots odd numbers balancing colouring integers factors number coordinates chocolate the only crossnumber geometry dodecagons pascal's triangle chalkdust crossnumber proportion cards cryptic crossnumbers hexagons dates perimeter dice advent products digits regular shapes shape dominos gerrymandering percentages elections digital clocks games cube numbers grids sport 2d shapes unit fractions triangles folding tube maps speed star numbers squares taxicab geometry crosswords calculus palindromes graphs irreducible numbers crossnumber division sums wordplay polygons quadratics multiples sum to infinity range tiling cryptic clues median logic rectangles differentiation time people maths fractions routes numbers functions mean circles area lines ellipses indices crossnumbers ave surds

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2020