mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2018

18 December

There are 6 terms in the expansion of \((x+y+z)^2\):
$$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz$$
Today's number is number of terms in the expansion of \((x+y+z)^{16}\).

Show answer

Tags: algebra

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2024

Advent calendar 2023

Advent calendar 2022

Advent calendar 2021


List of all puzzles

Tags

floors range digital products books factorials averages coordinates digital clocks symmetry logic christmas sport the only crossnumber colouring lines graphs irreducible numbers speed clocks binary algebra sums neighbours volume sets sum to infinity pascal's triangle addition division polygons cryptic clues rugby chocolate hexagons tournaments prime numbers remainders partitions differentiation circles multiplication cubics integration probability planes consecutive numbers perimeter triangles mean shape integers numbers ellipses square grids cards products perfect numbers calculus 2d shapes albgebra quadrilaterals means digits factors indices triangle numbers square numbers 3d shapes determinants percentages elections geometric means menace scales dominos dates geometry complex numbers square roots probabilty functions palindromes medians polynomials ave crossnumbers spheres doubling money coins routes odd numbers advent cube numbers squares grids cryptic crossnumbers tangents games axes regular shapes chess proportion area number wordplay pentagons decahedra parabolas rectangles even numbers dice crosswords tiling people maths time gerrymandering chalkdust crossnumber dodecagons consecutive integers quadratics multiples folding tube maps star numbers geometric mean balancing matrices unit fractions trigonometry shapes sequences median numbers grids expansions taxicab geometry bases arrows surds angles powers combinatorics fractions

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2025