mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2018

18 December

There are 6 terms in the expansion of \((x+y+z)^2\):
$$(x+y+z)^2=x^2+y^2+z^2+2xy+2yz+2xz$$
Today's number is number of terms in the expansion of \((x+y+z)^{16}\).

Show answer

Tags: algebra

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2023

Advent calendar 2022

Advent calendar 2021

Advent calendar 2020


List of all puzzles

Tags

cubics factorials probabilty square roots people maths star numbers pascal's triangle even numbers geometric mean coins cryptic clues surds cryptic crossnumbers factors crossnumber quadrilaterals coordinates menace 3d shapes partitions circles planes rugby algebra square numbers tangents range squares area indices taxicab geometry division bases routes consecutive numbers crossnumbers sport consecutive integers volume functions colouring the only crossnumber median regular shapes fractions integration pentagons averages cube numbers gerrymandering shapes games books albgebra dodecagons triangles wordplay rectangles perimeter balancing crosswords matrices time money polygons geometry spheres advent proportion digital clocks remainders symmetry percentages sums parabolas hexagons sequences palindromes elections differentiation clocks tournaments multiplication numbers unit fractions dice odd numbers chess calculus grids number binary ellipses axes folding tube maps products 2d shapes triangle numbers addition quadratics prime numbers arrows shape expansions graphs polynomials combinatorics tiling floors logic complex numbers speed geometric means sets digits means cards perfect numbers chocolate christmas determinants multiples decahedra digital products angles probability scales chalkdust crossnumber dates irreducible numbers integers trigonometry mean sum to infinity doubling dominos lines ave

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2024