mscroggs.co.uk
mscroggs.co.uk

subscribe

Puzzles

Sum equals product

\(3\) and \(1.5\) are a special pair of numbers, as \(3+1.5=4.5\) and \(3\times 1.5=4.5\) so \(3+1.5=3\times 1.5\).
Given a number \(a\), can you find a number \(b\) such that \(a+b=a\times b\)?

Show answer & extension

Tags: numbers
If you enjoyed this puzzle, check out Sunday Afternoon Maths XXI,
puzzles about numbers, or a random puzzle.

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2023

Advent calendar 2022

Advent calendar 2021

Advent calendar 2020


List of all puzzles

Tags

regular shapes coordinates wordplay multiples indices games digital clocks polynomials spheres chocolate geometric means polygons odd numbers dates quadrilaterals range factorials integration lines irreducible numbers sport averages cubics division perimeter probabilty prime numbers chalkdust crossnumber taxicab geometry logic ave coins hexagons consecutive numbers shapes graphs mean people maths cryptic clues determinants sets unit fractions 2d shapes tiling integers digits binary books median area rugby multiplication partitions albgebra decahedra consecutive integers dice sequences crosswords dominos products folding tube maps sum to infinity geometry routes gerrymandering crossnumber elections triangle numbers proportion digital products addition speed percentages menace colouring volume advent planes combinatorics geometric mean square numbers parabolas doubling sums palindromes pascal's triangle squares clocks number square roots remainders balancing pentagons chess cards scales symmetry ellipses cube numbers probability crossnumbers complex numbers dodecagons matrices circles surds angles floors expansions grids the only crossnumber factors axes time money tournaments trigonometry tangents cryptic crossnumbers rectangles even numbers algebra calculus shape quadratics star numbers numbers 3d shapes triangles fractions perfect numbers arrows differentiation means functions bases christmas

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2024