Show me a random puzzle
 Most recent collections 


quadratics factorials square roots logic cryptic clues triangles shape advent dates indices chalkdust crossnumber coins multiples functions integration graphs christmas dice square numbers folding tube maps remainders parabolas shapes unit fractions integers number cryptic crossnumbers star numbers scales crosswords palindromes irreducible numbers 2d shapes digits money ellipses calculus triangle numbers sequences arrows rugby doubling sums percentages chocolate geometry grids wordplay dodecagons complex numbers books time angles differentiation planes balancing colouring circles people maths mean volume games perimeter cards algebra rectangles routes numbers fractions cube numbers lines squares prime numbers odd numbers polygons clocks surds factors symmetry coordinates chess ave addition multiplication area regular shapes sum to infinity bases hexagons 3d shapes spheres speed proportion floors crossnumbers trigonometry menace averages means pascal's triangle taxicab geometry partitions division probability sport perfect numbers probabilty


Show me a random puzzle
▼ show ▼

Backwards fours

If A, B, C, D and E are all unique digits, what values would work with the following equation?
$$ABCCDE\times 4 = EDCCBA$$

Show answer

If you enjoyed this puzzle, check out Sunday Afternoon Maths LXIV,
puzzles about multiplication, or a random puzzle.
© Matthew Scroggs 2019