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# Puzzles

## Archive

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## 10 December

The equation $$x^2+1512x+414720=0$$ has two integer solutions.
Today's number is the number of (positive or negative) integers $$b$$ such that $$x^2+bx+414720=0$$ has two integer solutions.

$$(x^2-7x+11)^{(x^2-11x+30)}=1.$$