mscroggs.co.uk
mscroggs.co.uk

subscribe

Puzzles

10 December

The equation \(x^2+1512x+414720=0\) has two integer solutions.
Today's number is the number of (positive or negative) integers \(b\) such that \(x^2+bx+414720=0\) has two integer solutions.

Show answer

Powerful quadratics

Source: nrich
Find all real solutions to
$$(x^2-7x+11)^{(x^2-11x+30)}=1.$$

Show answer

Archive

Show me a random puzzle
 Most recent collections 

Sunday Afternoon Maths LXVII

Coloured weights
Not Roman numerals

Advent calendar 2018

Sunday Afternoon Maths LXVI

Cryptic crossnumber #2

Sunday Afternoon Maths LXV

Cryptic crossnumber #1
Breaking Chocolate
Square and cube endings

List of all puzzles

Tags

cryptic crossnumbers speed chalkdust crossnumber sum to infinity dodecagons money factorials sequences division odd numbers people maths means chocolate proportion squares rectangles palindromes sport cards number square roots perfect numbers routes scales logic perimeter spheres geometry remainders games volume addition differentiation integration coins books christmas dates area 3d shapes grids time dice parabolas symmetry cryptic clues colouring percentages indices fractions mean averages circles folding tube maps polygons multiplication balancing taxicab geometry algebra planes bases numbers regular shapes factors graphs surds triangles shape ellipses prime numbers crossnumbers floors rugby coordinates wordplay angles calculus cube numbers crosswords advent integers irreducible numbers sums hexagons lines multiples doubling unit fractions complex numbers trigonometry 2d shapes partitions clocks square numbers triangle numbers shapes functions arrows pascal's triangle probabilty star numbers quadratics probability chess ave digits menace

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2019