mscroggs.co.uk
mscroggs.co.uk

subscribe

Advent calendar 2019

7 December

The sum of the coefficients in the expansion of \((x+1)^5\) is 32. Today's number is the sum of the coefficients in the expansion of \((2x+1)^5\).

Show answer

Tags: algebra

Archive

Show me a random puzzle
 Most recent collections 

Advent calendar 2023

Advent calendar 2022

Advent calendar 2021

Advent calendar 2020


List of all puzzles

Tags

menace bases axes albgebra taxicab geometry tiling scales ellipses graphs circles matrices probabilty means routes chess surds clocks area products games combinatorics digital products polygons decahedra dominos even numbers prime numbers 2d shapes shape doubling star numbers sums crossnumber factors elections sets calculus ave digits parabolas triangle numbers crossnumbers functions sport speed dates people maths fractions spheres the only crossnumber tangents grids pascal's triangle palindromes books volume pentagons quadratics partitions planes advent cryptic clues shapes square roots sequences chocolate expansions quadrilaterals hexagons differentiation median time determinants digital clocks gerrymandering percentages lines integration geometric means angles triangles cryptic crossnumbers coins consecutive numbers chalkdust crossnumber division irreducible numbers unit fractions geometric mean averages 3d shapes symmetry sum to infinity cards binary geometry numbers tournaments probability trigonometry crosswords indices perimeter floors rectangles dice perfect numbers algebra consecutive integers addition factorials integers complex numbers coordinates arrows multiplication odd numbers mean cube numbers polynomials cubics rugby balancing dodecagons christmas colouring number regular shapes remainders range multiples proportion logic squares square numbers money wordplay folding tube maps

Archive

Show me a random puzzle
▼ show ▼
© Matthew Scroggs 2012–2024